The answer is y= -6
my apologies if it’s wrong
You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
Answer:
14
Step-by-step explanation:
6×15=90 90-76=14 you save 14 dollars
Answer:
45.650 centimeters
Step-by-step explanation:
The height of a vase is 45.7 centimeters when rounded to the nearest tenth of a centimeter. What is the shortest possible height of the vase? Give your answer to 3 decimal places
Given that :
Height of vase = 45.7 when rounded to the nearest tenth
The shortest possible height of the vase : will be 45.65, this is because, the subsequent digit (hundredth) after the tenth digit is the figure rounded to give a tenth digit of 7
From the we know that the tenth digit before rounding is 7 - 1 = 6
And smallest possible value the hundredth placed digit could have in other to be rounded to 1 is 5.
To three decimal place, the thousandth placed value could take the least possible value in a digit series, which is 0
Hence, the shortest possible height of the vase = 4.650
