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Ad libitum [116K]
3 years ago
12

What are some of the applications for exponential functions?

Mathematics
1 answer:
frozen [14]3 years ago
4 0

Answer:

Some of the applications for exponential functions are:

1. model populations

2. carbon date artifacts

3. compound interest

hope this helps!

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How do I <br> Divide. Write in simplest form
sladkih [1.3K]

Answer:

14/42

Step-by-step explanation:

Use the keep change flip strategy or butterfly multiply

6 0
3 years ago
Describe the graph that would be used to solve the equation-x^2 + 4 = x+2
Rzqust [24]

Answer:

The values of x are x = -2 and x= 1.

Step-by-step explanation:

The given equation -x²+4 = x+2 can be written in the form of two functions as

y = -x²+4 which is a function representing parabola and

y = x+2 which is a straight line.

Now we will solve the given equation to find their points of intersection on graph. Their points of intersections will be the answer.

-x²+4 = x+2

-x²+4-x = x+2-x

-x²-x+4 = 2

-x²-x+4-2 = 2-2

-x²-x+2 = 0

Or x²+x-2=0

Now we will factorize the equation.

x²+2x-x-2=0

x(x+2)-1(x+2) = 0

(x+2)(x-1) = 0

x+2 = 0 ⇒x = -2

x-1 = 0 ⇒x = 1

For x = 1, y will be 3

and for x = -2, y will be 0

Now we can see the graph for the given coordinates (-2,0) and (1,3).



5 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
The Khan family is constructing a backyard and needs your help with a design that will fit their budget. The backyard is in the
Nonamiya [84]

Answer:

2x1000=2000m

Step-by-step explanation:

6 0
3 years ago
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Write 20.65 in expanded notation
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Answer:

2 * 10 + 6 * .1 + 5 * .01

Step-by-step explanation:

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