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cricket20 [7]
3 years ago
12

For most answers, you will simply enter your numeric answer directly into the space provided to the right of the equal sign. Ans

wer the following question by typing the numerical answer into the answer box. If you have a gross of items, you have 144 items. If you buy a gross of eggs, how many dozen eggs do you have
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

12 dozens of eggs I believe

Step-by-step explanation:

12 eggs are in one dozen

<em>Divide</em><em> </em><em>1</em><em>4</em><em>4</em><em> </em><em>by</em><em> </em><em>1</em><em>2</em><em>. </em><em> </em><u>1</u><u>4</u><u>4</u><u>÷</u><u>1</u><u>2</u><u>=</u><u>1</u><u>2</u>

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A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0&lt;=t&lt;=60
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Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

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3 years ago
What is the equation of a line that passes through the points (1,6) and (2,1)?
algol13

Answer:

y = -5x+11

Step-by-step explanation:

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3 years ago
Use the tape diagram to answer the following question: 8 is 40% of what number?
Blababa [14]
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The employees of a company were surveyed on questions regarding their educational background (college degree or no college degre
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Answer: D) 0.733.

Step-by-step explanation:

Let C denotes the number of employees having college degree and S denote the number of employees are single.

We are given ,

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Then,

n(C\cup S)=n(C)+n(S)-n(C\cap S)\\\\=400+100-60=440

Now, the probability that an employee of the company is single or has a college degree is

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Hence, the probability that an employee of the company is single or has a college degree is 0.733

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Find the real solution<br><br> x^4-x^3+2x^2-4x-8=0
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There's 2 solution, x= -1 and x= 2

Step-by-step explanation:

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