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3 years ago

The weight of 1000 identical samples of a substance is 1 pound. What is the weight of 100 samples?

Mathematics

2 answers:

alex41 [277]3 years ago

8 0

The answer is 0.1 lbs. Or 1/10 lbs.

Hope this helps!

finlep [7]3 years ago

3 0

Cross multiplication. 1000/1 = 100/p 100 x 1=100 100/1000= 0.1 answer= 0.1 pounds

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soldier1979 [14.2K]

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Step-by-step explanation:

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3 years ago

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Elena-2011 [213]

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3 years ago

If candy canes cost .89 a dozen,how much would it cost to buy candy canes for a school with 400 students

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3 years ago

Plz help me with this

never [62]

A) is right
b) just subtract ljm and kjm so 145-48 = 92°
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3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago