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sergey [27]
3 years ago
15

A 4.0 L container stores 4.0 grams of an unknown gas at 2.3 atm of pressure and 30.0 degrees Celsius. What is the molar mass of

the unknown gas?
0.37 g/mol
0.093 g/mol
11 g/mol
3.7 g/mol
Chemistry
2 answers:
dusya [7]3 years ago
6 0
11g/mol


hope this helps
Masja [62]3 years ago
3 0
Correct answer is 11 g/ mol
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A basketball player jumps straight up to dunk a basketball. The basketball player's speed increases as she returns to the
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Options :

The upward force is greater than the downward force.

The downward force is greater than the upward force.

The rightward force is greater than the leftward force.

The leftward force is greater than the rightward force.

Answer:

The downward force is greater than the upward force.

Explanation:

When the player jumps to dunk a basket ball, it requires an upward force exerted on the person due to the push by the person to jump, after dunking the basket ball, the player attains maximum height, where his final velocity becomes zero and his direction changes (from upward to downward), at this point his velocity increases due to the additional force exerted on the player due to the Earth's Gravitational pull - which is a downward force which acts on an object).

Hence, it could be concluded that the increase in speed of the basketball player as she returns to the ground means that the downward force is greater than the upward force acting on the player.

7 0
2 years ago
Salt water is best described as _______.
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Answer:

Salt water is, A. a mixture

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3 years ago
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CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

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Right answer is option d that o is oxidized.
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