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Zarrin [17]
2 years ago
11

The mass of 900. atoms of sodium(Na)

Chemistry
1 answer:
ivanzaharov [21]2 years ago
7 0

Answer:

3.44 × 10⁻²⁰ g Na

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

900 atoms Na

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

<u>Step 3: Convert</u>

<u />900 \ atoms \ Na(\frac{1 \ mol \ Na}{6.022 \cdot 10^{23} \ atoms \ Na} )(\frac{22.99 \ g \ Na}{1 \ mol \ Na} ) = 3.4359 × 10⁻²⁰ g Na

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.4359 × 10⁻²⁰ g Na ≈ 3.44 × 10⁻²⁰ g Na

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Explanation:

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  • c is the concentration of the solution. c = 0.25 \;\text{M} = 0.25\;\text{mol}\cdot\textbf{L}^{-1} for the initial solution.
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What's the concentration of the diluted solution?

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  • n is the number of solute in the solution. Diluting the solution does not influence the value of n. n = 0.03375\;\text{mol} for the diluted solution.
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The least significant number in the question comes with 2 sig. fig. Keep more sig. fig. than that in calculations but round the final result to 2 sig. fig. Hence the result: 0.021 M.

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