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artcher [175]
3 years ago
8

How is a gamete different from other types of cells in a person's body?

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0
The human gametes differ from all the other cells in the body because the somatic cells have a complete set of chromosomes
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Answer it answer it answer it
Archy [21]

Answer:

A

Explanation:

A chemical change is when a new substance is created, which often has its own chemical properties, so A is the correct answer.

4 0
3 years ago
Positron emission of technetium-95
NNADVOKAT [17]
Idk it’s making me answer a question in order to get help on my own
5 0
3 years ago
Of the metals pb hg na and mg which will not spontaneously donate electrons to copper in solution
marta [7]

Answer : Hg (Mercury)


Explanation : In the given series of elements Na falls after the Cu in the reactivity series, for Pb it also falls after Cu, and for Mg it is the same.


Only Hg which is mercury can spontaneously donate its electrons to copper in the solution because it falls before Cu in the reactivity/activity series.

3 0
3 years ago
Read 2 more answers
(multiple choice) What is the SI unit of mass?
SpyIntel [72]

Answer:

Gram

Explanation:

The SI unit of mass is grams.

Mass is the measure of matter contained in a substance. It is usually determined by weighing an amount of substance on a balance or scale.

  • Mass is a fundamental quantity
  • So, the unit of mass is grams.
  • Ounce and pounds are other units but not the standard one.
  • Newton is the unit of force and weight.
5 0
2 years ago
Melts in the system pb-sn exhibit regular solution behavior. at 473°c apb = 0.055 in a liquid solution of xpb = 0.1. calculate t
Masteriza [31]
Given the temperature 746 K and activity of Pb equal to 0.055. The mole fraction of Pb is 0.1. So, the mole fraction of Sn = 0.9.Activity coefficient, γ = 0.055 / 0.1 = 0.55.The expression for w=ln⁡〖γ_Pb x RT〗/(X_Sn^2 )=(-0.5978 x 8.314 J/(mol K ) x 746 K)/(0.9 x 0.9)= -4577.7 J= -4578 J

Now we use the computed value above and new temperature 773 K. The mole fraction of Sn and Pb are 0.5 and 0.5 respectively. Calculate the activity coefficient in the following manner.lnγ_Sn=w/RT  X_Pb^2=(-4578 J)/(8.314 J/mol  x 773 K)  x 0.5 x 0.5= -0.718lnγ_Sn=exp⁡(-0.178)=0.386The activity of  Sn= γ_Sn  x X_Sn=0.386 x 0.5=0.418
w of the system is -4578 J and the activity of Sn in the liquid solution  of xsn at 500 degree Celsius is 0.418
6 0
3 years ago
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