Answer:
I'm sure but send thru this picture for the question so I can help.
Answer:
Explanation:
a ) Total mixture = 4.656 g
Sand recovered = 2.775 g
percent composition of sand in the mixture
= (2.775 g / 4.656 g ) x 100
= 59.6 % .
b )
Total of sand and salt recovered = 2.775 g + .852 g = 3.627 g .
Total mixture = 4.656 g
percent recovery = (3.627 / 4.656 ) x 100
= 77.9 % .
Answer:
Ethyl methyl ether.
Explanation:
- The mono ether is named commonly by <em>dividing the molecule into two parts, writing them in alphabetical order, and adding ether in the end of the name.</em>
- In this compound; we have two parts CH₃ (methyl) and CH₃CH₂ (ethyl).
So, it is named ethyl methyl ether.
- The IUPAC name of this name is Methoxyethane.
Hello!
How many molecules are in 30 liters of methane (CH4) at STP ?
We have the following information:
Knowing that by Avogadro's Law for each mole of substance we have 6.02 * 10²³ molecules, it is known that in STP (Standard Temperature and Pressure) one mole of any gas equals 22.4 L, then:
22.4 L ----------------- 6.02*10²³ molecules
30 L -------------------- y molecules
multiply the means by the extremes
Answer:
8.0625*10²³ molecules of methane
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Answer: I don't know. I am sorry.
Explanation: Because I don't understand your question. I am so, so, so sorry.
