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Mila [183]
3 years ago
11

4.6 x 105 How many significant figures?

Chemistry
1 answer:
nordsb [41]3 years ago
6 0

Answer:

2

Explanation:

4.6 has two figures.  The 10^5 tells us only that it is a very large number, but adds nothing that tells us the number was any more accurately measured than what was provided in the 4.6

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They are eukaryotic, which means they have a nucleus. Most have mitochondria

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Give the result of the following expression with the correct number of significant figures
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84 m/s x 31.221 s = 2600 m
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Which compounds represent the
Firlakuza [10]

Answer:

Both

compounds in left hand side of the equation is called reactants.

compounds in right hand side of the equation is called products.

so ans is both water and carbon di oxide

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3 0
2 years ago
The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

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2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

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8 0
3 years ago
Which chemical in the atmosphere of Titan (a moon of Saturn) plays the same role that water plays on the Earth by producing "rai
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Answer:

Methane (CH₄)

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Acid rain is a type of precipitation that occurs in the earth and it results in the release of a certain amount of methane gas (CH₄). Similarly, there also occurs precipitation in Titan but it releases CH₄ instead of water.  This methane is responsible for the increasing amount of temperature.

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7 0
3 years ago
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