Answer:
The value of H is (1/3)
Step-by-step explanation:
i found it by dividing the value of G on 2
Step-by-step explanation:
All the 5 rows of the coefficient matrix (since it is of order 5×8) will have a pivot position. The augmented matrix obtained by adding a last column of constant terms to the 8 columns of the coefficient matrix will have nine columns and will not have a row of the form [0 0 0 0 0 0 0 0 1]. So the system is consistent.
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
To find that you would do (such that x is the unknown) 3x+5(x+2)=106
and if you do this you will find that x=12
so the two numbers you are looking for are 12 and 14
Using the picture, we know (2x+6)+(5x-3)=24. Simplify to find x.
7x+3=24
7x=21
x=3
We know AB=2x+6, and x=3. Plug 3 in for x.
AB=2(3)+6.
AB=6+6
AB=12