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Alika [10]
4 years ago
7

A standard mercury thermometer consists of a hollow glasscylinder, the stem, attached to a bulb filled with mercury. As thetempe

rature of the thermometer changes, the mercury expands (orcontracts) and the height of the mercury column in the stemchanges. Marks are made on the stem to denote the height of themercury column at different temperatures such as the freezing point(0 C ) and the boiling point (100 C ) of water. Othertemperature markings are interpolated between these twopoints.Due to concerns about the toxic properties of mercury,many thermometers are made with other liquids. Consider drainingthe mercury from the above thermometer and replacing it withanother, such as alcohol. Alcohol has a coefficient of volumeexpansion 5.6 times greater than that of mercury. The amount ofalcohol is adjusted such that when placed in ice water, thethermometer accurately records 0 C. No other changes are made tothe thermometer.Part AWhen the alcohol thermometer is placed in 22 C water,what temperature will the thermometer record?less than 22 C22 Cgreater than 22 CPart BWhen the alcohol thermometer is placed in a -12 Csubstance, what temperature will the thermometer record?less than-12 C-12 Cgreater than -12 CPart CIf you want to design a thermometer with the same spacingbetween temperature markings as a mercury thermometer, how must thediameter of the inner hollow cylinder of the stem of the alcoholthermometer compare to that of the mercury thermometer? Assume thatthe bulb has a much larger volume than the stem.5.6 times wider√5.6 times widerthe same diameter but different bulbsize√5.6 times smaller5.6 times smaller
Physics
1 answer:
Debora [2.8K]4 years ago
6 0

Answer:

this is way too long....

Explanation:

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Answer:

k =  5.05 N/m

Explanation:

In order to calculate the spring mass of the system, you use the following formula:

T=2\pi \sqrt{\frac{m}{k}}     (1)

T: period of oscillation of the system

m: mass of the air-track glider = 200g = 0.200 kg

k: spring constant = ?

You first calculate the period of oscillation:

T=\frac{1}{f}=\frac{1}{12/15.0s}=1.25s

Next, you solve the equation (1) for k, and then you replace the values of the other parmateres:

k=4\pi^2 \frac{m}{T^2}\\\\k=4\pi^2 \frac{0.200kg}{(1.25s)^2}=5.05\frac{N}{m}

The spring constant of the spring is 5.05 N/m

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3 years ago
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Hello! ^^

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