Answer:
d. 103.3
Explanation:
In the given question, the National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. And the units of atmospheric pressure used for reporting the atmospheric pressure data are inches of mercury. For a barometric pressure of 30.51 inches of mercury, we can calculate the pressure in kPa as follow:
In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.
Therefore, a barometric pressure of 30.51 inches of mercury corresponds to _____103.3_____ kPa.
First, we divide the number of atoms of silicon given in the problem above by Avogadro's number 6.6022 x10^23. This will give us the number of moles of silicon. Then, we multiply the number of moles by the molar mass of silicon.
number of moles = (3.6 x 10^20 atoms/6.022x10^23 atoms) = 5.97x10^-4 moles
Then, multiplying by the molar mass
(5.97x10^-4 moles)(28.0855 g/mol) = 0.017 grams
Answer:
(a). second order.
(b). zeroth order.
(c). one and a half order.
(d). third order.
Explanation:
Hello,
In this case, you just have to add the concentration's powers in each rate law:
(a) ![r=k[NO_2]^2](https://tex.z-dn.net/?f=r%3Dk%5BNO_2%5D%5E2)
Just the 2-power is present, so it is a second order law.
(b) 
No power is present, so it is a zeroth order law.
(c) ![r=k[H_2]*[Br_2]^{1/2}](https://tex.z-dn.net/?f=r%3Dk%5BH_2%5D%2A%5BBr_2%5D%5E%7B1%2F2%7D)
1 plus 1/2 gives 1.5, that is why it is a 1.5 (one and a half) order law.
(d) ![r=k[NO_2]^2[O_2]](https://tex.z-dn.net/?f=r%3Dk%5BNO_2%5D%5E2%5BO_2%5D)
2 plus 1 gives 3, that is why it is a third order law.
Best regards.
Answer:
Potential Energy is stored energy or energy of position (gravitational). The object isn't moving. For example, a ball being held is potential energy because the object isn't moving but it has the potential of turning into kinetic energy.
Kinetic Energy is the energy of motion. For example, running. You are moving, and there is clear action and activity
