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Diano4ka-milaya [45]
3 years ago
7

Beaker A contains 100.0 g of water initially at 10EC. Beaker B contains 100.0 g of water initially at 20°C. The contents of the

two beakers are mixed. What is the final temperature of the contents? Assume that there are no heat losses and that the mass of the beakers is negligible. Useful data: The specific heat of water is 4.18 J/(g°C) Question 2 options: A. 15.0°C B. 17.5°C C.12.5°C D.10.0°C
Chemistry
2 answers:
Korvikt [17]3 years ago
7 0

Answer:

(A) 15.0 °C

Explanation:

The water in beaker A gains heat because its initial temperature (10 °C) is less than the initial temperature of the water in beaker B (20 °C) which loses heat.

Let T3 be the final temperature

Heat gained by beaker A = heat loss by beaker B

mc(T3 - T1) = mc(T2 - T3)

The mass and specific heat of water in both beakers are the same. Therefore, (T3 - T1) = (T2 - T3)

T1 is initial temperature of beaker A = 10 °C

T2 is initial temperature of beaker B = 20 °C

T3 - 10 = 20 - T3

T3 + T3 = 20 + 10

2T3 = 30

T3 = 30/2 = 15 °C

Masteriza [31]3 years ago
5 0

Answer:

Explanation:

Given:

Cp of water = 4.18 J/g.°C

Mass of beaker 1 and 2, M1 = M2

= 100 g

Initial temperature of beaker 1, Ti1 = 10°C

Initial temperature of beaker 2, Ti2 = 20°C

Delta H1 = -delta H2

The heat lost by one besjef is gained by the other.

Delta H = M × Cp × delta T

Delta T = tempf - Ti

100 × 4.18 × (10 - x) = -100 × 4.18 × (20 - x)

4180 - 418x = -8360 + 418x

836x = 12540

x = 15°C

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5 0
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5. A penny weighs about 2.5 g. How many moles of pennies would be required to equal the mass of the moon (7.3x10^24 kg)
schepotkina [342]

5. 1.16 x 10^{26} moles  moles of pennies would be required to equal the mass of the moon.

6. 12.86 moles of ethanol are in a 750 ml bottle of vodka.

Explanation:

5 .Data given:

mass of penny = 2.5 grams

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moles present in mass of the moon given as = 7.3 x 10^{24} kg

number of moles = \frac{mass}{atomic mass of  1 mole}

number of moles = \frac{2.5}{62.93}

0.039 moles of penny is present in 2.5 grams

0.039 moles of penny in 2.5 grams of it

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6.

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vodka = 40% ethanol

volume of vodka bottle = 750 ml

moles of ethanol =?

density of ethanol =0.79 g/ml

atomic mass of ethanol = 46.07 grams/mole

so, from the density of ethanol given we can calculate how much ethanol is present in the solution.

density = \frac{mass}{volume}

density x volume = mass

0.79 x 750 = 592.5 grams

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles of ethanol = \frac{592.5}{46.07}

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