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3 years ago

Which term refers to the process by which ions that have entered solution are kept in solution?

Chemistry

2 answers:

wel3 years ago

4 0

The answer is C) Hydration

meriva3 years ago

4 0

Answer : The correct option is, hydration

Explanation :

Hydration : It is a process in which the ion or substance combines with water and kept in the solution. In the hydration process the solvent is water molecule.

For example : When the sodium chloride is dissolved in the water then the positive sodium ion get surrounded by the water molecule through their oxygen ends and the negative chloride ion get surrounded by the water molecule through their hydrogen ends.

$NaCl+H_2O\rightarrow NaOH+HCl$

Dissociation : It is a process in which the compound splits or dissociates into to two or more smaller ions, atoms or particles.

Electrolyte : it is a process in which the a molecule is completely dissociates into their respective ions in the aqueous solution.

Ionization : It is a process in which a molecule acquire a positive or negative charged by the gaining or losing electrons.

Hence, the correct option is, hydration.

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Consider the following chemical reaction: 2KCl + 3O2 --> 2KClO3. If you are given 100.0 moles of KCl and 100.0 moles of O2...

g100num [7]

Answer:

O₂; KCl; 33.3

Explanation:

We are given the moles of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

2KCl + 3O₂ ⟶ 2KClO₃

n/mol: 100.0 100.0

1. Identify the limiting reactant

(a) Calculate the moles of KClO₃ that can be formed from each reactant

(i)From KCl

$\text{Moles of KClO}_{3} = \text{100.0 mol KCl} \times \dfrac{\text{2 mol KClO}_{3}}{\text{2 mol KCl}} = \text{100.0 mol KClO}_{3}$

(ii) From O₂

$\text{Moles of KClO}_{3} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KClO}_{3}}{\text{3 mol O}_{2}} = \text{66.67 mol KClO}_{3}$

O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.

KClO₃ is the excess reactant.

2. Moles of KCl left over

(a) Moles of KCl used

$\text{Moles used} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KCl}}{\text{3 mol O}_{2}} = \text{66.67 mol KCl}$

(b) Moles of KCl left over

n = 100.0 mol - 66.67 mol = 33.3 mol

3 0

3 years ago

Shale forms from tiny particles of which material?

miskamm [114]

Answer:

a. mica

Explanation:

6 0

3 years ago

What does GCAT help us remember?

vazorg [7]

It helps us remember the four bases of dna

7 0

3 years ago

Which of the following conclusions can be made about the use of mercury and alcohol thermometers?

boyakko [2]

Answer:

Explanation:

The answer is C

3 0

2 years ago

If the mass of an object is 6 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?

Solnce55 [7]

Using formula:

$w = m\times g$ -(1)

where w is weight of object,

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 6 lbm (given)

acceleration of gravity, g = $32.0 ft/s^{2}$ (given)

Now, substituting the values in equation (1):

$w = 6 lbm \times 32 ft/s^{2} = 192 lbmft/s^{2}$

Since, $1 lbf = 32.174 lbm ft/s^{2}$

So, $w = 192\times \frac{1}{32.174 lbf}$

$w = 5.976 lbf$

Hence, the mass of an object is 5.976 lbf.

8 0

3 years ago