The final solution had a volume of 1.0L and a molarity of 0.925. How many moles of Nickel (II) chloride were present in the solu tion? Show your work.
1 answer:
Answer:
0.925 mole
Explanation:
From the question given, the following were obtained:
Volume = 1.0L
Molarity = 0.925 M
Number of mole of Nickel (II) chloride =?
Molarity is simply defined as the mole of solute per unit litre of the solution.
It is represented mathematically as:
Molarity = mole /Volume
With the above equation, we can easily find the mole of Nickel (II) chloride present in the solution as follow:
Molarity = mole /Volume
0.925 = mole / 1
Mole = 0.925 x 1
Mole of Nickel (II) chloride = 0.925 mole
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