Ask question

Ask question

All categories

2 years ago

11

Mr.Norman has agreed to drive 4 students to their gymnastics practice. If one student rides in the front seat and three students

ride in the back, in how many ways can the 4 students be arranged on the car?

1 answer:

Mashutka [201]2 years ago

3 0

Its just that one way it can be arranged

You might be interested in

Which data collections show bias? Check all that apply

Natalija [7]

Answer:

Those answers are correct that are shown and that are shown in blue

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Can anyone help me find the (?,?) coordinates? The given shape is a parallelogram.

Sonja [21]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Given shape is a parallelogram.

Construction: Draw a line joining the diagonals.

<em>In parallelogram, diagonals bisect each other.</em>

Solve it using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

Using this midpoint find the missing coordinate.

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinates and y-coordinates.

$$ \frac{m+h}{2}=\frac{x}{2}, \ \ \ \frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x, n = y

x = m + h and y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

7 0

2 years ago

Cos^(2)x=(cscxcosx)/(tanx+cotx)

bixtya [17]

$\cos^2 x = \dfrac{\csc x \cos x}{\tan x + \cot x}$

$\cos^2 x = \dfrac{\csc x \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin x}{\cos x} \times 
\frac{\sin x}{\sin x} + \frac{\cos x}{\sin x} \times \frac{\cos x}{\cos 
x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{1}{\sin x \cos x}}$

$\cos^2 x = \csc x \cos x \sin x \cos x$

$\cos^2 x = \dfrac{1}{\sin x} \cos x \sin x \cos x$

$\cos^2 x = \cos^2 x$

6 0

3 years ago

Need help asap with work

Dominik [7]

Answer:

f(n)=2+4n

Step-by-step explanation:

when they are combined, there are two taken away, so we can just say that there are two added in total, and the number of grey hexagons is n, and it would be 4n because there are 2 taken away like i said earlier if that makes sense :)

6 0

2 years ago

The formula A=200e^.033t models the population of a particular city, in thousands, t years after 1998. When will the population

svetoff [14.1K]

Answer:

In the year 2010

Step-by-step explanation:

we have

$A=200e^{0.033t}$

where

A is the population in thousands

t is the number of years since 1998

so

For A=297 thousands

substitute and solve for t

$297=200e^{0.033t}$

simplify

$1.485=e^{0.033t}$

Apply ln both sides

$ln(1.485)=ln[e^{0.033t}]$

$ln(1.485)=(0.033t)ln(e)$

Remember that

$ln(e)=1$

$ln(1.485)=(0.033t)$

$t=\frac{ln(1.485)}{0.033}$

$t=12\ years$

1998+12=2010

7 0

2 years ago