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DENIUS [597]
3 years ago
14

Find the perimeter of A(-3,2), B(6,6), and C(7,-1).Please show work.

Mathematics
1 answer:
Furkat [3]3 years ago
3 0

AB=√{(6+3)²+(6-2)^2}=√(81+16)=√(97)

BC=√((7-6)²+(-1-6)²)=√(50)=5√2

AC=√((7+3)²+(-1-1)²)=2√(26)

Perimeter=AB+BC+AC=√97+5√2+2√(26)

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Ian wants to paint a wall measuring 3 metres by 7 metres.
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Whole numbers greater than 9 but less than 14
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6 0
3 years ago
(15.2*0.25-48.51/14.7)/x=(13/44-2/11-5/66/2.50)1.2/(3.2+0.8(5.5-3.25)
goldfiish [28.3K]

Answer:

x = 41.67

Step-by-step explanation:

The above equation, would be simplified or divided into parts;

Therefore, the given equation becomes;

A/x = B/C

Where;

A = (15.2*0.25-48.51/14.7)

B = (13/44-2/11-5/66/2.50)1.2

C = 3.2+0.8(5.5-3.25)

x = unknown variable.

<u>Part A</u>

(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)

A = (3.8 - 3.3)

A = 0.5

<u>Part B</u>

(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2

B = 0.09 * 1.2

B = 0.108

<u>Part C</u>

(3.2+0.8(5.5-3.25)

C = 4*(2.25)

C = 9

<em>Substituting the values into the equation, we have;</em>

0.5/x = 0.108/9

<em>Cross-multiplying, we have;</em>

9 * 0.5 = 0.108x

4.5 = 0.108x

x = 4.5/0.108

x = 41.67

6 0
2 years ago
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