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kicyunya [14]
3 years ago
15

Write an equation that shows the relationship between x and y.

Mathematics
1 answer:
svp [43]3 years ago
8 0
Write an equation to describe the relationship between the corresponding values of x and y shown in the table.
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To better understand how a function works, you will have to find the ___ that
erma4kov [3.2K]

Answer:

rule

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
write an equation using ''x'' and then solve the equation. on the new year eve there were 7,580 tons of cargo loaded in the morn
vovikov84 [41]

Answer:  12,997 - 7,580 = x

x= 5417

Step-by-step explanation: 12,997 - 7580 = 5417

Hope this helps

8 0
3 years ago
Below are two parallel lines with a third line intersecting them.
Allushta [10]
180-48= 132 ( I think)
8 0
2 years ago
I need help with number 3
yan [13]
First check whether the point (-6,8) is the solution to any of the equations. To check, just plug in the x and y values of the points into the equation and see if they give you a true statement. 
5(-6)+3(8)=-6
-30+24=-6
-6=-6
That's a true statement so the point is the solution to the first equation.
2(-6)+(8)=-4
-12+8=-4
-4=-4
It is a true statement so the point is a solution for both equations
There are no other solution because lines can only intersect in one or infinite points, but that is only if they are the same lines, which is not true in this circumstance.
A. It is the only solution to the set. 
Hope this helps.
7 0
3 years ago
Read 2 more answers
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