Process energy required
1) raise the temperature to 75.0 °C 628 J
2) evaporate the liquid at 75.0°C 15.6 KJ = 15,600 J
3) raise the temperature to ? 712 J
Total energy: 628 J + 15,600 J + 712 J = 16,940 J
As you must have realized the clue to do the problem correctly is to convert all the energy values to joules, because you cant not add up joules with kilo joules.
Answer: 16,940 J
The limiting reagent is fully consumed during the reaction
Number of moles of NO2 = 11.5/(14+16x2) =0.250mol
Mole ratio: 4NO2 to 1O2
Number of moles of O2=0.250/4 =0.0625mol
Mass of O2 produced= 0.0625x32 =2g
Answer: B
Answer:
Hindi ko po alam pero subukan ko pong sagutan yan
1s2 2s2 2p6 3s2 3p6 4s2 is the electron configuration for Calcium