Answer:- 5.91%
Solution:- The given balanced equation is:
From given moles of zinc iodide we calculate the moles of zinc carbonate using mol ratio from the balanced equation and the moles are converted to grams on multiplying by molar mass.
= 
Molar mass of zinc carbonate is 125.38 gram per mol. Let's multiply the moles by molar mass to get the theoretical yield:
= 
theoretical yield is 213.15 g and the actual yield is given as 12.6 g.
percent yield = 
percent yield = 
= 5.91%
The percent yield of zinc carbonate is 5.91%.
Answer:
1) first order
2) zero order
3) second order
Explanation:
For a first order reaction, the concentration of the reactants varies exponentially with the rate of reaction. The curve of a first order reaction shows an exponential relationship between the rate of reaction and the change in the concentration of reactants.
For a zero order reaction, the rate of reaction is independent of the concentration of the reactants. So, regardless of the amount of reactant in solution, the rate of reaction is constant.
For a second reaction, the reaction rate increases in direct proportion to the concentration of the reactant in solution.
The answer will be D because the reaction is what's first(A) and then it is the product that comes out.
Answer: 15.850
Explanation:
The conversion used from liters to gallons is:
1 L = 0.264172 gallon
The conversion used from sec to min is:
60 sec = 1 min
1 sec =
We are asked: liters/sec = gallons/min
Therefore, to convert from liters/second to gallons/minute, multiply the number of liters/second by 15.850.
Explanation:
The given reaction is as follows.
Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,
Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] =
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the 
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that of the weak acid is 3.42.
