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nikklg [1K]
3 years ago
10

What should iron oxide be categorized

Chemistry
2 answers:
salantis [7]3 years ago
6 0

Answer:

as a result of oxidation

Explanation:

iron + oxygen ---} iron oxide

11111nata11111 [884]3 years ago
5 0

Answer:

What are you doing stepbro?

Explanation:

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Vinil7 [7]

Answer:

do not know

Explanation:

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3 years ago
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List these compounds in order of decreasing carbon–carbon bond strength: hcch, h2cch2, h3cch3. rank from strongest to weakest.
ycow [4]
The strongest bond strength is of HCCH (Ethyne), then comes H₂CCH₂ (Ethene) and H₃CCH₃ (Ethane) has the least bond strength as compare to Ethyne and Ethene.

                                      HCCH > H₂CCH₂ > H₃CCH₃
               Strongest ----------------------------------------------> Weakest

Explanation:
                     
Ethyne has triple bond, one sigma bond and two pi bonds, Hence, a greater overlap is found between two carbon atoms which resulted in shortening the bond length (i.e 1.9 Angstrome). Also carbon carbon triple bond has highest force constant value i.e 15 ×10⁵ dyne/cm which is greater than carbon carbon double bond (10 ×10⁵ dyne/cm) and single bond (5 × 10⁵ dyne/cm). 
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3 years ago
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aniked [119]
The decoders of the DNA messege
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4 years ago
How did thinking about collision theory help you think about the effect of social distancing?
melomori [17]

Answer:

When two people "collide" and one of them is carrying the virus then the other person starts carrying it. This is why we need to social distance so it doesn't spread.

Explanation:

3 0
3 years ago
The decomposition of N I 3 to form N 2 and I 2 releases − 290.0 kJ of energy. The reaction can be represented as 2N I 3 (s)→ N 2
ella [17]

Answer:

The change in enthaply when 10.0 g of nitrogen triiodide decomposes is -3.67 kJ.

Explanation:

2NI_3 (s)\rightarrow N_2 (g)+3 I_2 (g), \Delta H_{rxn} =-290.0 kJ

Enthalpy of the reaction when 2 moles of nitrogen triiodide decomposed =\Delta H_{rxn}

\Delta H_{rxn} = -290.0 kJ

Enthalpy of the reaction when 1 moles of nitrogen triiodide decomposed :

\Delta H=\frac{\Delta H_{rxn}}{2}=\frac{-290.0 kJ}{2} =-145.0 kJ

Mass of nitrogen triiodide decomposed = 10.0 g

Moles of nitrogen triiodide = \frac{10.0 g}{395 g/mol}=0.02532 mol

Change in enthaply when 0.02532 moles of nitrogen triiodide decomposed:

\Delta H\times 0.02532=-145 kJ\times 0.02532=-3.67 kJ

3 0
3 years ago
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