It is an alkaline earth metal.
Answer: False
Explanation: just took on edge
Explanation:
In a galvanic cell, the cathode is positively charged and the anode is negatively charged.
The cathode attracts electron while the anode donates or releases electrons.
Electrons received - Cathode
Electrons donated - Anode
Hydrophilic;
Polar compounds
water
ions
glucose
Hydrophobic;
Triglycerides
cholesterol
Lipids
Oil
Carbohydrates
<h3>What are hydrophilic substances?</h3>
The term hydrophilic substances is used to describe the substances that could dissolve in water. They are those substances that are water soluble. Somehow, the substances must be polar because in chemistry like dissolves like.
The hydrophobic substances are those substances that do not dissolve in water. They are nonpolar and interact with other nonpolar substances.
The classification of the substances took place below;
Hydrophilic;
Polar compounds
water
ions
glucose
Hydrophobic;
Triglycerides
cholesterol
Lipids
Oil
Carbohydrates
Learn more about hydrophilic substances:brainly.com/question/4692308
#SPJ1
Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.
Explanation:
- d = m/V, where d is the density, m is the mass and V is the volume.
- We have the mass m = 0.50 g, so we must get the volume V.
- To get the volume of a gas, we apply the general gas law PV = nRT
P is the pressure in atm (P = 1.5 atm)
V is the volume in L (V = ??? L)
n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).
- Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
- Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
