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romanna [79]
3 years ago
10

What is the relationship between the number of particles in a substance, the number of moles, and the mass of the substance

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles

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balandron [24]
Hi!

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6 0
3 years ago
En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

5 0
3 years ago
A chunk of copper has a volume of 1.45 mL and a mass of 12.93 grams. What is the density of the chunk of copper?
natta225 [31]

Answer:

Density = 8.92 \ g/mL

Explanation:

The equation for density is:

Density = \frac{mass}{volume}

We plug in the given values:

Density = \frac{12.93 \ g}{1.45 \ mL}

Density = 8.92 \ g/mL

7 0
2 years ago
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AlekseyPX
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4 0
3 years ago
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xenn [34]

Answer:

1231

Explanation:

nnfjjkdnsggjnSVDDK and that how u get the answer i a grammer

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