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ivolga24 [154]
3 years ago
5

Solve using elimination. 2x + y = 5 x - 3y = 6

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

then substitute y in eq 1 to get x

hope this helped you

Please mark as the brainliest (ㆁωㆁ)

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A basketball court is 94 feet by 50 feet. Eight fans ca
IgorC [24]

Answer:

The entire floor can contain approximately 4178 fans

Step-by-step explanation:

The first step is to calculate the area of the basketball floor.

we can do this by multiplying the length by the breadth as such 94 X 50 = 4700 square feet.

The second step is to calculate the area occupied by 8 of the fans. We can do this by multiplying 3 ft by 3ft = 9 square feet.

From this, it will be easier to estimate the area occupied by only one fan. This can be got by dividing 9 square feet by 8.  

This is = 1.125 square feet.

To get the number of students it can occupy, we divide the total area of the court by the area occupied by one student.

4700/ 1.125 =4177.8 \approx 4178 fans

4 0
3 years ago
For which division problems should you write the first digit of the quotient in the hundreds place?
Levart [38]
D is the right answer
4 0
3 years ago
Read 2 more answers
Find the equation of the line parallel to y=2x+6 passing through (4,5)
ozzi

Answer:

y=2x-3

when two lines are parallel, they have the same slope.

in the formula y=mx+b, m=slope of the line

we know 2 will be the slope for the line passing through (4,5)

next plug in (4,5) into the formula with 2 as the slope

4=x 5=y

next 5=2(4)+b

and you end up with

y=2x-3 when you simplify

3 0
3 years ago
Please tell me the right answer
Alexus [3.1K]

Answer:

is probably y=-2x

Step-by-step explanation:

6 0
3 years ago
S the expression x3•x3•x3 equivalent to x3•3•3
Artyom0805 [142]
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution



so the solutions are
x=-∛3, 0, ∛3
3 0
3 years ago
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