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romanna [79]
3 years ago
5

If a boat and its riders have a mass of 1200 kg and the boat drifts in at 1.8 m/s how much work does sam do to stop it?

Physics
1 answer:
Ksju [112]3 years ago
8 0
M = 1200 kg, the mass of the boat and its occupants
v = 1.8 m/s, the speed of the boat

The KE (kinetic energy) of the boat is
KE = (1/2)*m*v²
     = 0.5*(1200 kg)*(1.8 m/s)²
     = 1944 J

To stop the boat, the work done should be equal to the KE of the boat.
Therefore the work done is 1944 J.

Answer:  1944 J

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A football kicker kicks a ball with a mass of .42 kg. The average acceleration of the football was 14.8 m/s squared. How much fo
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3 years ago
Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long. How long is the ot
s344n2d4d5 [400]

Answer:

The length of the longer pipe is L = 2.30 m

Explanation:

Given that:

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.

How long is the other pipe?

From above;

The formula for the frequency of open ended pipes can be expressed as:

f = \dfrac{nv}{2L}

where n = 1 ( since half wavelength exist between those two pipes)

v = 343 m/s  and L = 2.08 m

Thus, the shorter pipe produces a frequency of :

f = \dfrac{1*343}{2*2.08}

f = \dfrac{343}{4.16}

f =82.45 \ Hz

Also; we know that the beat frequency was given as 8.0 Hz

Then,

The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz

The lower frequency of the longer pipe = 74.45 Hz

Finally;

From the above equation; make Length L the subject of the formula. Then,

The length of the longer pipe is L = \dfrac{nv}{2f}

The length of the longer pipe is L = \dfrac{1*343}{2*74.45}

The length of the longer pipe is L = \dfrac{343}{148.9}

The length of the longer pipe is L = 2.30 m

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