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3 years ago

14

When describing the scientific evidence, what is the meaning of the word repeatable?

1 answer:

muminat3 years ago

7 0

Hello there,
The word 'repeatable' means, the scientific experiment is repeated in the same way, with the same methods and analysis.

Hope this helps :))

~Top

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In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.

denis23 [38]

The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.

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3 years ago

You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gasoline and

andreev551 [17]

Answer:

v_avg = 37 km/h

Explanation:

To find the average velocity in the complete trajectory you use the following formula:

$v_{avg}=\frac{v_1+v_2}{2}$ ( 1 )

v1: velocity in the first part of the trajectory = 70 km/h

v2: velocity in the second part of the trajectory = ?

You calculate v2 by using the following equation for a motion with constant velocity:

$v_2=\frac{2.0km}{30min}*\frac{60min}{1h}=4\frac{km}{h}$

you replace the values of v1 and v2 in (1) and you obtain:

$v_{avg}=\frac{70km/h+4km/h}{2}=37\frac{km}{h}$

hence, the average velocity is 37 km/h

6 0

2 years ago

Read 2 more answers

During a collision, a 63.9-kilogram driver of a car moving at 24 m/s is brought to rest by an inflating airbag in 1.2 seconds. W

kaheart [24]

Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

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2 years ago

Sixty-three joules of heat are added to a closed system. The initial internal energy of the system is 58 J, and the final intern

MakcuM [25]

I posted this because I got it correct. The answer is 28J.

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2 years ago

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Single Stage 0.0/3.0 points (graded) Consider a rocket carrying 100,000 kg of propellant, 10,000 kg of structure, and 5000 kg of

Nonamiya [84]

Answer: The Propellant fraction is 0.87.

The payload fraction is 0.04.

Δv = 8991.81 m/s

Explanation: To determine the fractions, first, calculate the total mass of the rocket:

$m_{t} = m_{prop} + m_{str} + m_{pay}$

$m_{t} = 100,000 + 10,000 + 5,000$

$m_{t} = 115,000$

The Propellant Fraction will be

$m_{prop} = \frac{m_{prop}}{m_{t}}$

$m_{prop} = \frac{100,000}{115,000}$

$m_{prop} =$ 0.87

The Payload Fraction is:

$m_{pay} = \frac{m_{pay}}{m_{t}}$

$m_{pay} = \frac{5,000}{115,000}$

$m_{pay} =$ 0.04

The value of Δv is calculated by the formula:

Δv = $-V_{e}. ln(\frac{m_{final}}{m_{initial}} )$

The exhaust velocity ( $V_{e}$ ) is:

$V_{e} = g_{0}.Isp$

$V_{e} =$ 9.81*450

$V_{e} =$ 4414.5

$m_{final}$ is the total mass after the rocket consume all the propellant and $m_{initial}$ is the total mass before the action.

Δv = $-V_{e}. ln(\frac{m_{final}}{m_{initial}} )$

Δv = $-4414.5.ln(\frac{15,000}{115,000} )$

Δv = - 4414.5.ln(0.13)

Δv = 8991.81

Δv will be 8991.81 m/s.

7 0

2 years ago