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tamaranim1 [39]
3 years ago
11

What is 127 as a percent?

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Hello!

The answer is 127,000%

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Use the mapping to determine which of the following are elements of the range.
Vadim26 [7]

Answer:

The elements of the range are the birthdays.

Step-by-step explanation:

A function is a distinct sort of relation in which each element of the domain is combined with precisely one element in the range. A mapping displays how the elements are combined.

A mapping figure comprises of two parallel columns. The 1st column signifies the domain of a function, and the other column for its range.  

Lines or arrows are drawn from domain to range, to signify the relation between any two elements.

A function denoted by the mapping, in which each element of the range is combined with accurately one element of the domain is called one-to-one mapping.

From the diagram provided it is clear that the function denoted by the mapping is an one-to-one mapping.

The elements of the range are:

Birthday : {January 5 , January 7 , February 24 , March 1 , April 7 , May 30 , July 20 , August 1 , November 13 , November 26 }

Thus, the elements of the range are the birthdays.

6 0
3 years ago
20.8 divided by 100 how is the decimal point moved
alukav5142 [94]

Answer:

Two points to the left

Step-by-step explanation:

20.8/100 = 0.208

The number was 20.8, but now the new number moved

1. 2.08

2. 0.208

So my answer is two decimal points to the left.

I hope this helped!

6 0
2 years ago
Describe how you would plot a line that has a starting point at (2,-3) and a slope of 3/4
Nadya [2.5K]
You put the first cross on (2,-3) then go 3 to the right and 4 up. If it was a negative 3 you would go to the left. Negative 4 you would go down.
6 0
3 years ago
A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
2 years ago
the height of a stack of books ,h inches,is directly proportional to the number of books, n.Tbe height of a stack of 10 books is
kotegsom [21]

Step 1

\begin{gathered} \text{Height(h)}\propto number\text{ of books(n)} \\ H\propto n \\ \text{Adding k the constant of proportionality} \\ H\text{ = kn} \\ k=\frac{H}{n} \end{gathered}

Step 2

A)Find the constant of proportionality K when n = 10 books and h = 12 inches

k=\frac{12}{10}=1.2

Step 3

B) Write an equation that relates H and n by substituting for k

H=1.2n

Step 4

C) Find the height, H of the stack of 24 books

\begin{gathered} H\text{ }=\text{ 1.2 }\times24 \\ H=28.8\text{inches} \end{gathered}

8 0
11 months ago
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