About oxidation and reduction, write a definition of each in your own words

Need this answered ASAP

prohojiy [21]

The concentration of the final solution will be 0.2886 M.

<h3>Molar concentration</h3>

50.6 g of NaCl is dissolved in 600 mL of water.

Mole of 50.6 g NaCl = 50.6/58.44 = 0.8658 mol

Molar concentration of the oiriginal solution = 0.8658/06 = 1.4431 M

25 mL of 1.4431 M of the solution is diluted up to the 125 mL mark.

m1 = 1.4431, v1 = 25 ml, v2 = 125 mL

m2 = m1v1/v2 = 1.4431 x 25/125 = 0.2886 M

The concentration of the final solution will be 0.2886 M

More on molar concentration can be found here: brainly.com/question/15532279

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7 0

2 years ago

We immerse an iron strip Fe in a copper (II) sulfate solution (CP+ + S0?) which has a blue

Tom [10]

Answer:

5

Explanation:

7 0

3 years ago

A volumetric pipette has an uncertainty of 0.01cm3. What are the lowest and highest possible volumes for a measurement of 0.20cm

Anarel [89]

Answer:

Possible lowest volume = 0.19 cm

Possible highest volume = 0.21 cm

Explanation:

given data

volumetric pipette uncertainty = 0.01 cm³

total volume = 0.20 cm³

solution

we will get here Possible lowest and highest volume that is express as

Possible lowest volume = total volume - uncertainty .....................1

Possible highest volume = total volume + uncertainty ....................2

put here value in both equation and we get

Possible lowest volume = 0.20 cm - 0.01 cm

Possible lowest volume = 0.19 cm

and

Possible highest volume = 0.20 cm + 0.01 cm

Possible highest volume = 0.21 cm

3 0

3 years ago

How does percent composition by mass contribute to writing a balanced equation?

Mariulka [41]

Answer:

mass composition is very essential in obtaining a balanced equation

Explanation:

to have a completely balanced equation that means the right hand side being your reactants must be equal to the right hand side being your product. both sides need to have equal mass composition, when calculating the mass composition make sure both sides are equal if not consider revisiting the number of moles on both sides to ensure they all balance

5 0

3 years ago

Suppose 110.0 mL110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen

Fittoniya [83]

Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

H₂ + F₂ → 2HF

<h3>What is Ideal Gas ?</h3>

An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.

It is expressed as:

PV = nRT

where,

P = Pressure

V = Volume

n = number of moles

R = Ideal gas constant

T = temperature

Here,

P = 1 atm [At STP]

V = 110 ml = 0.11 L

T = 273 K [At STP]

R = 0.0821 [Ideal gas constant]

Now put the values in above expression

PV = nRT

1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K

$n = \frac{1\ \text{atm} \times 0.11\ L}{0.0821\ \text{L. atm/ K. mol} \times 273\ K}$

n = 0.0049 mol

<h3>How to find the concentration of resulting solution ? </h3>

To calculate the concentration of resulting solution use the expression

$C = \frac{n}{V}$

$= \frac{0.0049}{0.15}$

= 0.032 M

Thus from the above conclusion we can say that Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

Learn more about the Ideal Gas here: brainly.com/question/25290815
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4 0

2 years ago