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2 years ago

Many of these microscopic organisms are _____, or unicellular.

Chemistry

2 answers:

NikAS [45]2 years ago

5 0

Answer:

Microbe

Explanation:

It can be microbe or microorganisms.

Delvig [45]2 years ago

5 0

It’s either micro or microorganisms

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Which solution whose POH is 12

lesya692 [45]

Answer:

Explanation:

H3O =1×10_12=12 ooh is 12

3 0

2 years ago

A substance releases 2,192 J of heat, changing its temperature from 50 degrees C to 5 degrees C. The mass of the substance is 73

Gre4nikov [31]

The specific heat capacity of the given substance is -0.66 J/g°C.

<u>Explanation:</u>

The heat absorbed by any substance is the product of its mass, specific heat capacity and change in temperature.

q = m × c × ΔT

m is the mass in grams

q = amount of heat released or absorbed in J

ΔT = change in temperature in °C = 5 -50 = -45°C

c = specific heat capacity in J/g°C

c = $$\frac{q}{m \times dT}$

Plugin the values, we will get,

c = $$\frac{2192 }{73.9 \times-45}$

= -0.66 J/g°C

3 0

3 years ago

Arrange the following bonds in order of increasing ionic character. assign number 1 as the highest and 6 as the lowest. a. carbo

SIZIF [17.4K]

Answer: Potassium to fluorine, fluorine to nitrogen, bromine to hydrogen, carbon to hydrogen, lithium to chlorine, sodium to chlorine.
Explanation:
Ionic bond is greater when the electronegativity difference existing between the two atoms are large causing the bonding to be more polar.

5 0

2 years ago

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

$p^o_{H_2}=0.0035 atm$

$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

5 0

3 years ago

2.3 x 10²¹ particles H = __________ mol H (round to the nearest thousandth)

Natalka [10]

Taking into account the definition of avogadro's number, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ particles are contained in 1 mole of H, then 2.3×10²¹ particles are contained in how many moles of H?

amount of moles of H= (2.3×10²¹ particles × 1 mole)÷ 6.023×10²³ particles

<u><em>amount of moles of H= 3.82×10⁻³ moles</em></u>

Finally, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

Learn more about Avogadro's Number:

<u>brainly.com/question/11907018?referrer=searchResults </u>

<u>brainly.com/question/1445383?referrer=searchResults </u>

<u>brainly.com/question/1528951?referrer=searchResults</u>

7 0

2 years ago