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katen-ka-za [31]
2 years ago
10

Many of these microscopic organisms are _____, or unicellular.

Chemistry
2 answers:
NikAS [45]2 years ago
5 0

Answer:

Microbe

Explanation:

It can be microbe or microorganisms.

Delvig [45]2 years ago
5 0
It’s either micro or microorganisms
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The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

the answer and explanation is in the picture

hope this helps

please like and Mark as brainliest

8 0
3 years ago
Given the reaction _K(s) +_ Cl2(g) → _KCl(s) what is the amount of K, in grams, needed to completely react with 2 moles of Cl2(g
damaskus [11]

Answer:

156.4g K

Explanation:

I'm not sure if it is correct but I think it should be this

What do we know so far?: 2K + 1Cl2 -> 2KCl, 2 mol of Cl2

What are we looking for?: #g of K

What is the ratio of K to Cl2?: 2:1

Set up equation: 2molCl2 x \frac{2mol K}{1 mol Cl2}

Cancel unwanted units: 2 x \frac{2mol K}{1}

Answer we got: 2 x 2mol K = 4mol K

Converting moles to grams: 4 x 39.1 (molar mass of K) = 156.4g K

3 0
3 years ago
Round to 4 significant<br> figures.<br> 153.587
Tanzania [10]
I believe 153.6 is the answer.
4 0
3 years ago
Read 2 more answers
Imagine that you have a metal bar sitting half in the sun and half in the dark. On a sunny day, the part of the metal that has b
babunello [35]

Answer:

It will feel hot.

Explanation:

The part of the metal that has been sitting in the sun will heat up, and because metal is a good conductor,<em> the part sitting in the sun will heat up the part sitting in the dark</em>.

We say metal is a good conductor because it has<em> high thermal conductivity</em>, which mean heat will flow from the hot section of the bar to the cold section of the bat.

6 0
3 years ago
A ball of mass 0.2 kg is dropped from a height of 10 m. How much mechanical energy does it have right before it hits the ground?
lana [24]

Answer:

19.6 J  

Step-by-step explanation:

Before the ball is dropped, it has a <em>potential energy </em>

PE = mgh

PE = 0.2 × 10 × 9.8

PE = 19.6 J

Just before the ball hits the ground, the potential energy has been converted into kinetic (<em>mechanical</em>) energy.

KE = 19.6 J

3 0
3 years ago
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