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nirvana33 [79]
3 years ago
14

Kay is a student in Mrs. Hudson’s class. Assuming you know nothing else about Kay, what is the probability that Kay’s birthday w

ill fall on a weekday in any given year?
1. List the sample space for this problem.

2. Which outcome (or outcomes) of the sample space composes the event?

3. Express the probability of Kay’s birthday falling on a weekday as a fraction and as a decimal.

4. Describe the probability of Kay’s birthday falling on a weekday as impossible, unlikely, neither likely nor unlikely, likely or certain. Justify your response.
Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

262/365

Step-by-step explanation:

So as you can see there is no more information aout Kay on her birthday, so the chances of her birthday being on a week day is given by the total number of the weekdays of the year between the total number of days in a year, so in 2019 there are 262 weekdays, divided by 365 you get the probability that Kay´s birthday falls on a weekday.

262/365=,7178=71,78%

So the probability of Kay´s brithday falling on a week day will be 71,72%

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Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

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c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

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3 years ago
Which statements are always true regarding the diagram? Select three options. m∠5 + m∠3 = m∠4 m∠3 + m∠4 + m∠5 = 180° m∠5 + m∠6 =
DanielleElmas [232]

Based on the triangle sum theorem, exterior angle theorem, the true statements are:

m∠5 + m∠6 = 180°

m∠2 + m∠3 = m∠6

m∠2 + m∠3 + m∠5 = 180°

<h3>What is the Triangle Sum Theorem and the Exterior Angle Theorem?</h3>

According to the triangle sum theorem, m∠2 + m∠3 + m∠5 = 180°.

Also, based on the exterior angle theorem, m∠2 + m∠3 = m∠6.

∠5 and ∠6 are a pair of linear angles, therefore: m∠5 + m∠6 = 180°.

In summary, the true statements about the diagram given are:

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Learn more about the triangle sum theorem on:

brainly.com/question/7696843

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