Consider the reduction of the rectangle
1 answer:
The question is incomplete. The complete question is as follows.
Consider the reduction of the rectangle. A large rectangle has a length of 16.8 feet and width of 2.3 feet. A smaller rectangle has a length of 4.5 feet and width of x feet. Not drawn to scale (The drawing is in the attachment). Rounded to the nearest tenth.
What is the value of x?
A. 0.1 feet
B. 0.6 feet
C. 1.6 feet
D. 2.0 feet
Answer: B. 0.6 feet
Step-by-step explanation: Two quantity are proportional if the ratio of them is constant. From the drawing and the question, we have that the two rectangles are proportional between them.
x =
x = 0.6
The width of the smaller rectangle is <u>0.6 feet</u>.
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Answer:
80
Step-by-step explanation:
Think of it as a Venn diagram. One circle is the people who like dogs, and one circle is the people who like cats. The overlap is people who like both dogs and cats.
190 people in the survey said they like dogs. That includes the people who like both dogs and cats.
141 people in the survey said they like cats. That includes the people who like both dogs and cats.
If we simply add the two numbers together, we'll be counting the overlap twice. So to find the total number of people who like dogs or cats, we have to subtract one overlap.
dogs or cats = 190 + 141 − x
Therefore:
190 + 141 − x + 88 = 339
419 − x = 339
x = 80
80 people said they liked both cats and dogs.
To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation: