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Maru [420]
4 years ago
12

When the force applied to an object increases, the motion of the object​

Physics
1 answer:
Elza [17]4 years ago
6 0

Answer:

Semen is the most important thing in the life cycle of life

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Which list includes the phase changes that require a loss of energy (heat)?
Lemur [1.5K]

Answer:

b  

Explanation:

because if you freeze somthing you do not gain heat you loss heat.

3 0
3 years ago
A woman parked on a slight incline observes that the car beside her starts moving forward at approximately 0.30 m/s. When she lo
Burka [1]
The lady would be moving at -0.30 m/s as she is moving against the positive direction that is established as forward.
4 0
3 years ago
Read 2 more answers
A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is __________ a
cupoosta [38]

Answer:

The final pressure will be 0.67 atm.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 10 L

V₂ = 15 L

P₁ = 1.0 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0}\times {10}={P_2}\times {15} atm

{P_2}=\frac{{1.0}\times {10}}{15} atm

{P_2}=0.67\ atm

<u>The final pressure will be 0.67 atm.</u>

8 0
3 years ago
A particle could have a charge of
tekilochka [14]
The correct answer is 
<span> (3) 3.2 × 10^−19 C

In fact, electric charge is quantized: the elementary charge is the charge of the electron, </span>e=1.6 \cdot 10^{-19} C, and every particle can only have an electric charge which is an integer multiple of this value. Of the options listed above, only option (3) is an integer multiple of the elementary charge: in fact, it corresponds to 2 times the electron charge:
2e=2 \cdot 1.6 \cdot 10^{-19} C=3.2 \cdot 10^{-19} C
7 0
3 years ago
A cell of e.m.f 1.5 v and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm and a resisto
sergejj [24]

Answer:

The current in the circuit is 0.15 Ampere

Explanation:

The given parameters of the cell are;

The electromotive force (e.m.f.) of the cell, E = 1.5 V

The resistance of the cell, r = 2.5 ohm

The resistance of the ammeter = 0.5 ohm

The resistance of the resistor = 7.0 ohm

The formula for the e.m.f., E of a cell is given as follows;

e.m.f. E = I·(R + r)

Where;

I = The current in the circuit

R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω

Therefore, we have;

The \ current \ in \ the \ circuit, \  I = \dfrac{E}{R + r}

Substituting the known values, gives;

I = \dfrac{1.5 \ V}{7 \ \Omega  + 0.5 \ \Omega  + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A

The current in the circuit, I = 0.15 Ampere.

6 0
3 years ago
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