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Airida [17]
3 years ago
11

A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s. After 3s in the air, th

e canon hits it’s target. How far away(in meters) was the canon from its target? Answer:_____m
Physics
1 answer:
Vladimir [108]3 years ago
7 0

Answer:

60 m

Explanation:  

After 3 seconds of travel at 20 m/s, the projectile is 3·20 = 60 meters horizontally from the cannon.

__

The vertical height after 3 seconds is 0.9 m, so the straight-line distance from cannon to target is √(60^2 +0.9^2) ≈ 60.007 meters.

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Which of the following is the best example of kinetic energy being transformed into potential energy?
devlian [24]

Answer:

coasting down hill on a bicycle

Explanation:

Coasting down the hill on a bicycle is a typical example of how kinetic energy is being transformed to potential energy in a system.

Kinetic energy is the energy due to the motion of a body, it can be derived using the expression below;

      K.E  = \frac{1}{2} m v²

Potential energy is the energy due to the position of a body. It can be derived using;

     P.E  = mgh

m is the mass

v is the velocity

g is the acceleration due to gravity

h is the height

Now, at the top of the hill, the potential energy is at the maximum. As the bicycle coasts down the potential energy is converted to kinetic energy.  

6 0
3 years ago
Read 2 more answers
A driver, traveling at 22.0 m/s, slows down her 2.00 x 103 kg car to stop for a red light. What work is done by the friction for
Artemon [7]
Some work will be done on friction between wheels and road but it is negligible compared to work done on friction on breaks. 

W = Ek = (m*v^2)/2 = 2000*22^2/2 = 1000*22^2 = 484KJ

Because car is not changing its potential energy, there is no work to be done on while changing it which means that all goes on changing kinetic energy (energy of motion)
6 0
4 years ago
Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed of a
Pie

Answer:

Part a)

v = 7407.1 m/s

Part b)

v_{rel} = 1.05 \times 10^4 m/s

Explanation:

Part a)

As we know that orbital velocity at certain height from the surface of Earth is given as

v = \sqrt{\frac{GM}{R+h}}

here we know that

M = 5.98 \times 10^{24} kg

R = 6.37 \times 10^6 m

h = 900 km = 9.0 \times 10^5 m

now we have

v = \sqrt{\frac{(6.67 \times 10^{-11})(5.98 \times 10^{24})}{6.37 \times 10^6 + 9.0 \times 10^5}}

v = 7407.1 m/s

Part b)

When a loose rivet is moving in same orbit but at 90 degree with the previous orbit path then in that case the relative speed of the rivet with respect to the satellite is given as

v_{rel} = \sqrt{2} v

v_{rel} = 1.05 \times 10^4 m/s

6 0
3 years ago
An object-spring system undergoes simple harmonic motion with an amplitude A. Does the total energy change if the mass is double
son4ous [18]

Answer: No, The energy will remain the same

Explanation: Doubling the mass and leaving the amplitude unchanged won't have any effect on the total energy of the system.

At maximum displacement, E=0.5kA^2

Where E = total energy

K = spring constant

A = Amplitude

From the formula above : Total Energy is independent of mass,. Therefore, total energy won't be affected by Doubling the mass value of the object.

Also when the object is at a displacement 'x' from its equilibrium position.

E = Potential Energy(P.E) + Kinetic Energy(K.E)

P.E = 0.5kx^2

Where x = displacement from equilibrium position

E = Total Energy

K. E= E-0.5kx^2

From the relation above, total energy is independent of its mass and therefore has no effect on the total energy.

6 0
3 years ago
An athlete is working out in the weight room. He steadily holds 50 kilograms above his head for 10 seconds. Which statement is t
ludmilkaskok [199]
Answer: the true statement form the given statements is “the athletes is not doing any work because he does not move weight”

7 0
3 years ago
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