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TEA [102]
3 years ago
13

If a box is pulled straight across the floor at a constant speed and it is pulled with a horizontal force of 48 N., what is the

net force (in N) on the box.
Physics
1 answer:
Dima020 [189]3 years ago
7 0

If its speed is constant and it's moving in a straight line, THAT's "constant, uniform motion".  That can only happen when there's NO net force on the object.  

So besides the 48 N forward that the puller is giving it, there must be friction with the floor, or mosquitoes all over it trying to fly backwards, or somebody crouched down behind it pulling it backwards, or some other kinds of things going on, that all add up to 48 N BACKWARDS.

Somehow, the NET force on the box has to be <em>zero, </em>because of the way it's moving.

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Explanation:

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Explanation:

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M = ρ\frac{108}{3} π(r)^{3}    

So in conclusion, the mass of Earth and the mass of Big planet are related as M = 27m    

Now let's come to the Gravitational Force, we know that gravitational force is directly proportional to the mass of the body and inversely proportional to the radius.

→Suppose for Earth:  Mass = m, Radius = r  

For Big Planet:   Mass = M, Radius = R

\frac{m}{r^{2} } :  \frac{M}{R^{2} } = g : G

\frac{Gm}{r^{2} } =  \frac{gM}{R^{2} }

G =\frac{gMr^{2}}{mR^{2}}

→ Putting the value of R = 3r and M = 27m

G = \frac{g27mr^{2}}{m(3r)^{2}}

By cutting the terms, we get

G = 3g

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G = 3 x 9.8ms^{-2}  

G = 29.4 ms^{-2}  

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4 years ago
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3 years ago
Read 2 more answers
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Answer:

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3 years ago
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