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3 years ago

Hello! I need help with my math homework! I need it ASAP. 6x - 3 = -18 + x

Mathematics

2 answers:

uysha [10]3 years ago

6 0

Answer:

x = -3

Step-by-step explanation:

6x - 3 = -18 + x

Subtract x from each side

6x-x - 3 = -18 + x-x

5x -3 = -18

Add 3 to each side

5x-3+3 = -18+3

5x = -15

Divide each side by 5

5x/5 = -15/5

x = -3

Dima020 [189]3 years ago

4 0

Answer:

x = -3

Step-by-step explanation:

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What is the value of x? <br><br>Enter your answer in the box.

scoray [572]

Answer:

x=11

Step-by-step explanation:

Since the lines in the middle are parallel, we know that both sides are proportional to each other.

6:48 can be simplified to 1:8

Since we know the left side ratio is 1:8, we need to match the right side with the same ratio

We can multiply the ratio by 5 to match 5:3x+7

5:40

5:3x+7

Now we can set up the equation: 40=3x+7

Subtract 7 from both sides

3x=33

x=11

5 0

3 years ago

The price is three for $1.48 how much will one pepper cost?

mr Goodwill [35]

Answer:

$0.4933

Step-by-step explanation:

i guess

Just divided by 3 ;)

8 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago

Please answer thanks

nirvana33 [79]

Answer:

Step-by-step explanation:

it's kinda hard to explain

3 0

2 years ago

Giving 20 points and brainiest!

sladkih [1.3K]

Answer:

1/2,3/6,5/10,8/16

Step-by-step explanation:

they all equal 1/2

Im not sure if thats what it was asking but yea

6 0

3 years ago

Read 2 more answers