n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
The answer is "88.9%"
Step-by-step explanation:
The Variance percentage indicates through the REgression equation but, the R-Square, it becoming the determination coefficient. 88.871% of the variance could be explained according to the above results.
80$ won't be enough to pay
He would like need 6 more cents
he needs 80.06$
because
Answer:

Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<h3>y=-4x-9 and y=-4x-1</h3>
First, you have to substitute of y=-4x-1.
![\Longrightarrow: \sf{[-4x-1=-4x-9]}](https://tex.z-dn.net/?f=%5CLongrightarrow%3A%20%5Csf%7B%5B-4x-1%3D-4x-9%5D%7D)
<u>Add by 4x from both sides.</u>

<u>Solve.</u>

- <u>Therefore, the correct answer is "D. No solution".</u>
I hope this helps. Let me know if you have any questions.