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Gnoma [55]
4 years ago
10

In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percen

t yield of this reaction? *
85.0%
72.0%
75.0%
67.0%

Chemistry
1 answer:
CaHeK987 [17]4 years ago
3 0

Answer:

75.0%

Explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%

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The given question is incomplete. The complete question is:

An acidic solution at 25°C will have a hydronium ion concentration ________ and a pH value ________.

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