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Rudik [331]
4 years ago
8

Given: Quadrilateral DEFG is a parallelogram.

Mathematics
1 answer:
enyata [817]4 years ago
8 0

Answer:

A.  ΔDGH ≅ ΔFEH

Step-by-step explanation:

We are given the proof of GH ≅ EH and DH ≅ FH.

Now, previous to step 7, we have obtained,

Step 5: ∠HGD ≅ ∠HEF  and ∠HDG ≅ ∠HFE

Step 6: DG ≅ EF as opposite sides of a parallelogram are congruent.

<em>Since, we have that two angles of the triangles are congruent and their including sides are also congruent.</em>

Thus, by Step 7 i.e. ASA criterion for congruence, we get that the corresponding triangles are also congruent.

Hence, we get, ΔDGH ≅ ΔFEH.

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