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4 years ago

I really need help. My teacher said that I could use any number.

Mathematics

1 answer:

katen-ka-za [31]4 years ago

4 0

The keyword is Rise over run
So the 2nd y value minus the first y value and divide it by the 2nd x value minus
(y2-y1)/(x2-x1)
(10-7)/5-3)
the first x value and you should get 3/2
*dont worry the if the number is under and not above it’s not a saying to do to the power of but it’s just saying the order in which to put the x and y values.

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Help please I don’t get may I please have help with this

Veronika [31]

Answer:

$1)\:2\frac{2}{3} ft$

$2)\:4$

$3)\:\frac{20}{3} ft^{2}$

$4)\:10\frac{2}{3} ft^{2}$

------------------------

hope it helps...

have a great day!!

5 0

3 years ago

Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in in burrows per square kilometer
 $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the density of prairie dog burrows is approximately 2444 burrws per square kilometer.

5 0

3 years ago

I don’t understand number 89! please help I have a test tomorrow!

Rainbow [258]

V = rw

where; v = velocity , r = radius , w = angular speed

you're given the diameter = 0.5 miles so the radius = 0.25 miles

180 = (0.25)w
180/0.25 = w
720 radians per hour = w

2pi radians in 1 revolution

720 rad/hr * 1 rev / 2pi rad = 720/2pi rev/hr
= 114.6 rev/hr

8 0

3 years ago

When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.

Juliette [100K]

$x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0$

$Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution$

$x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \ 0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \ 0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \ 0$

$Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}$

6 0

3 years ago

I'm really bad at age chart problems. Can someone help me with this and provide an explanation?

Fed [463]

Answer: 10

Step-by-step explanation:

tony is 5 years younger than Marvin's age 1 year from now.

t = (m+1) - 5

t = m - 4

6 years ago tony was half as old as marvin was then.

t - 6 = 1/2(m - 6)

Get rid of the fraction, multiply both sides by 2

2(t-6) = m - 6

2t - 12 = m - 6

2t = m - 6 + 12

2t = m + 6

from the first statement, replace t with (m-4)

2(m-4) = m + 6

2m - 8 = m + 6

2m - m = 6 + 8

m = 14 is Marvin's present age

how old is tony now?

t = 14 - 4

t = 10 yrs is tony's age

4 0

3 years ago