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frutty [35]
3 years ago
10

In class we are using special sum formulas but don't know how to get the answer for this question

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0
You are referring to:

\sum\limits_{i=1}^{n}{i} = \frac{n(n+1)}{2}

You can solve your problem by calculating

\sum\limits_{i=1}^{525}{i} = \frac{525\cdot526}{2} = 138075

and then subtracting the first bit:

\sum\limits_{i=1}^{19}{i} = 190

So 138075 - 190 = 137885
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Calibrating a scale:
lana66690 [7]

Answer:

We conclude that the calibration point is set too high.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  1000 grams

Sample mean, \bar{x} =  1001.1 grams

Sample size, n = 50

Alpha, α = 0.05

Population standard deviation, σ = 2.8 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1000\text{ grams}\\H_A: \mu > 1000\text{ grams}

We use One-tailed(right) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{ 1001.1 - 1000}{\frac{2.8}{\sqrt{50}} } = 2.778

Now, z_{critical} \text{ at 0.01 level of significance } = 2.326

Since,  

z_{stat} > z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.

6 0
3 years ago
Solve:
Temka [501]

Answer:

a= -5

Step-by-step explanation

PEMDAS

8 0
3 years ago
On Monday, the rover traveled 330 cm. On Tuesday,it traveled 180 cm. If the rover stoped every 15 cm to recharge, how many more
boyakko [2]
10 more times

On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10

3 0
3 years ago
Which motion does the vector show?
Hatshy [7]
Right one unit and up ten units. Hope this helps!
3 0
4 years ago
Please answer quickly<br>expand and simplify: 4(5x-3y) (x-4y) -(3x-4y)(2x+3y)​
Gekata [30.6K]

Answer: 14x^2-93xy+60y^2 Hope that helps!

Step-by-step explanation:

1. Expand by distributing terms

(20x-12y)(x-4y)-(3x-4y)(2x+3y)

2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)

3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)

4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2

5. Collect like terms (20x^2-6x^2)+(-80xy-12xy-9xy+8xy)+(48y^2+12y^2)

6. Simplify.

And your answer would be 14x^2-93xy+60y^2

5 0
3 years ago
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