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jolli1 [7]
4 years ago
7

Explain how surface waves can have characteristics of both longitudinal waves and transverse waves. Please use 3 content related

sentences.
Physics
1 answer:
Anvisha [2.4K]4 years ago
8 0

Answer:

Surface waves can have characteristics of both longitudinal and transverse waves in the following way;

  1. The motion of the surface waves is up and down which is perpendicular to the direction of the wave. This is similar to the motion of transverse waves whereas the the motion of longitudinal waves is parallel.
  2. Energy is transferred in all these waves in the form of waves without the transportation of matter. The reason is that waves always originate from the source of its vibration.
  3. Surface wave also falls in the category of a mechanical wave, similar to longitudinal wave and transverse wave. Mechanical waves transfer energy through medium without transfer of matter, which is what surface, longitudinal and transverse waves do.

I hope the answer was helpful.

Thanks for asking

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Using 3rd equation of kinematics

\boxed{\Large{\sf v^2-u^2=2as}}

\\ \Large\sf\longmapsto v^2=u^2+2as

\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)

\\ \Large\sf\longmapsto v^2=576+768

\\ \Large\sf\longmapsto v^2=1344

\\ \Large\sf\longmapsto v=\sqrt{1344}

\\ \Large\sf\longmapsto v=36.6m/s

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What is NOT a raw minteral used in photosyntheisis
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Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o
Mrac [35]

Answer:

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

d = L\frac{\lambda}{\Lambda x}  (2)

Notice that it is necessary to express L and \lambda in units of millimeters.

L = 4m \cdot \frac{1000mm}{1m} ⇒ 4000mm

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Hence, the distance between the two slits is 1.2mm.

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