Answer:
(a) 1.16 s
(b)0.861 Hz
Explanation:
(a) Period : The period of a simple harmonic motion is the time in seconds, required for a object undergoing oscillation to complete one cycle.
From the question,
If 1550 cycles is completed in (30×60) seconds,
1 cycle is completed in x seconds
x = 30×60/1550
x = 1.16 s
Hence the period is 1.16 seconds.
(b) Frequency : This can be defined as the number of cycles that is completed in one seconds, by an oscillating body. The S.I unit of frequency is Hertz (Hz).
Mathematically, Frequency is given as
F = 1/T ........................... Equation 1
Where F = frequency, T = period.
Given: T = 1.16 s.
Substitute into equation 1
F = 1/1.16
F = 0.862 Hz
Hence thee frequency = 0.862 Hz
Answer:
16.8 seconds
Explanation:
Given that:
Constant speed of rabbit = 4.2 m/s
Initial Velocity (u) of cat = 0
Acceleration (a) of cat = 0.5 m/s²
Time it takes cat to catch rabbit ;
Using the relation:
Distance moved by rabbit (Dr) :
Dr = speed * time ; Dr = 4.2t
Distance moved by Cat (Dc) :
Dc = ut + 0.5at^2
Dc = 0 + 0.5at^2
Hence, Cat will catch rabbit when Dr = Dc
4.2t = 0.5at^2
4.2t = 0.5(0.5)t^2
4.2t = 0.25t^2
Divide both sides by t
4.2 = 0.25t
t = 4.2 / 0.25
t = 16.8 seconds
Hence, the cat will catch the rabbit after 16.8 seconds
The force applied to small piston = 2.2 x 10³ N
<h3>Further explanation</h3>
Given
a radius of 5 cm and 15 cm
weight 20000 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
A₁ = π.5²
A₂ = π.15²
F₁/ π.5² cm² = 20000/π.15² cm²
F₁ = 2222.22 N⇒2.2 x 10³ N
