Answer:
the distance traveled by Charlotte in feet is 338.44 ft
Explanation:
Given;
speed of Charlotte, u = 66.5 mi/h
time of motion, t = 3.47 s
The distance traveled by Charlotte in feet is calculated as;

Therefore, the distance traveled by Charlotte in feet is 338.44 ft
Answer:
Neutrons and protons are located in the nucleus of the atom.
Explanation:
And electrons are in the electron cloud.
1. 2504.63 J
2. 929.5m/s
Hope this helps :)
I can explain it as well if you’d like
Answer:
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Explanation:
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