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Stella [2.4K]
2 years ago
12

Can someone answer my last question you could get 25 points total​

Physics
1 answer:
enyata [817]2 years ago
5 0

Answer:

Hi where is question. Hope you understand me

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I need an answer ASAP .....
Harrizon [31]

Answer:

Hope this helped :

Explanation:

When light passes from a medium with one index of refraction (m1) to another medium with a lower index of refraction (m2), it bends or refracts away from an imaginary line perpendicular to the surface (normal line). As the angle of the beam through m1 becomes greater with respect to the normal line, the refracted light through m2 bends further away from the line.

At one particular angle (critical angle), the refracted light will not go into m2, but instead will travel along the surface between the two media (sine [critical angle] = n2/n1 where n1 and n2 are the indices of refraction [n1 is greater than n2]). If the beam through m1 is greater than the critical angle, then the refracted beam will be reflected entirely back into m1 (total internal reflection), even though m2 may be transparent!

4 0
3 years ago
Read 2 more answers
What is the initial vertical velocity?
Marat540 [252]

Answer:

Thus, any projectile that has an initial vertical velocity of 21.2 m/s and lands 10.0 m below its starting altitude spends 3.79 s in the air.The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .

3 0
2 years ago
Obtain a volume of 12.5 millimeters of liquid in the diagram
tiny-mole [99]

Answer:

D remove 1.5 ML of liquid.

Explanation:

     

5 0
3 years ago
Read 2 more answers
Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 50 km/h. After six hours,
Xelga [282]
A )
t 1 = 2 h,  t 2 = 6 h
Δ t = t 2 - t 1 = 6 - 2 = 4 h
54 = 50 + a Δ t
54 = 50 + 4 a
4 a = 54 - 4
4 a = 4
a = 4 : 4
a = 1 km/h²
v o = 48 km/h
An equation that can be used to describe the velocity of the car at the different times is:
v = 48 + t
B ) The graph is in the attachment. 
Download docx
6 0
3 years ago
At a distance D from a very long (essentially infinite) uniform line of charge, the electric field strength is 1000 N/C. At what
Alla [95]

Answer:

The correct option is (a).

Explanation:

We know that, the E is inversely proportional to the distance as follows :

E=\dfrac{k}{d^2}

We can write it as follows :

\dfrac{E_1}{E_2}=(\dfrac{d_2}{d_1})^2

Put all the values,

\dfrac{1000}{2000}=(\dfrac{d_2}{d})^2\\\\\sqrt{\dfrac{1000}{2000}}=(\dfrac{d_2}{D})\\\\0.7071=\dfrac{d_2}{d}\\\\d_1=0.7071D\\\\d_1=\dfrac{D}{\sqrt2}

So, the correct option is (a).

5 0
3 years ago
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