Answer:
The value of Kc is 9.33 * 10^-17
Explanation:
Step 1: Data given
Temperature = 1000 K
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Step 2: Calculate Kc for N₂ (g) + 2 O₂ ⇌ N₂O₄
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
2 NO₂ (g) ⇌ N₂O₄ (g) = 1/Kc = 1 / 1.5 * 10^6 = 6.67 *10^-7
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Kc = Kc1 * Kc2
Kc = (6.67 *10^-7) * (1.4 * 10^-10)
Kc = 9.33 * 10 ^-17
The value of Kc is 9.33 * 10^-17
Answer:
Mass = 100.8 g
Explanation:
Given data:
Mass of sulfur formed = ?
Mass of water formed = 37.4 g
Solution:
Chemical equation:
2H₂S + SO₂ → 3S + 2H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 37.4 g/ 18 g/mol
Number of moles = 2.1 mol
Now we will compare the moles of water and sulfur.
H₂O : S
2 : 3
2.1 : 3/2×2.1 = 3.15
Mass of sulfur:
Mass = number of moles × molar mass
Mass = 3.15 mol × 32 g/mol
Mass = 100.8 g
Answer:
We are to write the orbital notation and electronic configuration of sulfur and iron.
The orbital notation shows the filling of electrons into orbitals or sublevels.
Electron configuration shows the distribution of electrons into shells;
Number of electrons Electron configuration Orbital notation
S 16 2 8 6 1s² 2s² 2p⁶ 3s² 3p⁴
Fe 26 2, 8, 14 2 1s² 2s² 2p⁶ 3s² 3p⁶3d⁶4s²
Explanation:
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