Answer:
Make nitrous oxide or laughing gas by heating ammonium nitrate and collecting the vapor by bubbling it up into a container over water. ... It's easy to make nitrous oxide or laughing gas at home or in the lab. All you need is a heat source and ammonium nitrate
Explanation:
As we know,
Density of Benzene = 876 Kg/m³
And,
Density of Water = 997 Kg/m³
So,
Specific Gravity is calculated as,
Specific Gravity = Density of Benzene / Density of Water
Specific Gravity = 876 Kg/m³ / 997 Kg/m³
Specific Gravity = 0.878
Every object having specific gravity less than 1 will float on water and if value is greater than 1 then it will sink.
Benzene being non-polar in nature does not mix with water and due to less density it will float on the surface of water.
The equation of state for a hypothetical ideal gas is known as the ideal gas law, sometimes known as the general gas equation. i.e. PV = nRT or P1V1 = P2V2.
- According to the ideal gas law, the sum of the absolute temperature of the gas and the universal gas constant is equal to the product of the pressure and volume of one gram of an ideal gas.
- Robert Boyle, Gay-Lussac, and Amedeo Avogadro's observational work served as the basis for the ideal gas law. The Ideal gas equation, which simultaneously describes every relationship, is obtained by combining all of their observations into a single statement.
- When applying the gas constant R = 0.082 L.atm/K.mol, pressure, volume, and temperature should all be expressed in units of atmospheres (atm), litres (L), and kelvin (K).
- At high pressure and low temperature, the ideal gas law basically fails because molecule size and intermolecular forces are no longer negligible but rather become significant considerations.
Learn more about ideal gas law here:
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Answer:
Explanation:
Hello there!
In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:
In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:
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