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Irina18 [472]
2 years ago
12

Complete the balanced chemical reaction for the following weak base with a strong acid. In this case, write the resulting acid a

nd base as its own species in the reaction.
Chemistry
1 answer:
abruzzese [7]2 years ago
7 0

Firstly, the <u>complete question </u>would be:

Complete the balanced chemical reaction for the following weak base with a strong acid. In this case, write the resulting acid and base as its own species in the reaction.

NH₃(aq)+HCl(aq)→

<u>Solution:</u>

In this reaction, the hydrogen from the HCl is taken up by ammonia.

So, the balanced chemical reaction would be:

NH₃ (aq) + HCl (aq)  ----> NH₄⁺ (aq)  + Cl⁻ (aq)

The chorine ion (Cl⁻) is the basic, whereas ammonium (NH₄⁺) is the acid.

<h3><u>What are acid- Base reaction ?</u></h3>

Both biology and industrial chemistry depend on acid-base reactions. In addition, we frequently come across acids or bases in our houses, grocery stores, and pharmacies. For instance, antacids are bases whereas aspirin is an acid (acetylsalicylic acid). Actually, every home cook who has made mayonnaise or marinated fish with lemon juice has performed an acid-base reaction. Let's first go over some of the features of these reactions before moving on to the characteristics of acids and bases.

A material is said to be an acid if it dissolves in water to form H+ ions, whereas a substance is said to be a base if it dissolves in water to form OH- ions. In actuality, this is the only set of definitions that could exist. The definitions of acids and bases have evolved significantly as scientists have learned more about them, despite the fact that the general characteristics of acids and bases have been known for more than a thousand years.

To learn more about acid-base reactions, refer to:

brainly.com/question/15220646

#SPJ4

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The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
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Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

T1 (initial temperature in Kelvin)= 303.15

V2( final volume)= ?

T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

V2= (V1/T1) ×T2

V2=(0.75/303.15) ×273.15

V2=0.67577931717

V2= 0.68L

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