To do this problem, add up all the numbers and divide by the amount of numbers:

1.01+1.03+.98+.99+1.01+1.02+.98+1.05+.97+.98
10.02

Now divide by 10 (the amount of samples)

10.02/10
1.002

The Mean of the Data Set is 1.002

Hope this helps!

8 0

3 years ago

Read 2 more answers

Tameka built 1/2 of a shed on Monday and 2/5 of the shed on Tuesday. Tameka finished building the shed of Wednesday. What fracti

Doss [256]

Step One

Find the sum of the fractions for Monday and Tuesday

1/2 + 2/5

The common denominator for these 2 days is 10

1/2: 1*5/(2*5) = 5/10

2/5:2*2/(2*5) = 4/10

Add these two equivalent fractions together.

5/10 + 4/10 = 9/10

The first 2 days resulted in 9/10 of the shed being completed.

Step Two

Find out how much (in terms of fractions) is left of the shed.

Let the whole shed = 1

Let what has been done = 9/10

What remains is 1 - 9/10 = 1/10

Answer: 1/10 of the shed needs to be done

4 0

3 years ago

Please help, I will mark brainliest.

Bess [88]

Answer:

Step-by-step explanation:

Total number of students who roller skated = 80

Number of students who roller skated with laser tag = 39

Number of students who roller skated with no laser tag = 80 - 39 = 41

Therefore, percentage of students who roller skated with no laser tag = $\frac{41}{154}\times 100$ = 27%

Since, number of students who played laser tag = 85

Percentage of students who played laser tag = $\frac{85}{154}\times 100$ = 55%

Total number of students who played no laser tag = 45% of 154 = 69

Number of students with no roller skates and no laser tag = 69 - 41 = 28

Percentage of students with no roller skates and no laser tag = $\frac{28}{154}\times 100$

= 18%

Percentage of students who played with no rollers skates = (30 + 18)%

= 48%

Laser tag No laser tag Total

Roller skate 25% 27% 52%

No Roller skate 30% 18% 48%

Total 55% 45% 100%

7 0

3 years ago