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xz_007 [3.2K]
3 years ago
10

It costs Marie $25 overhead and then an additional $1.25 to make each barrette. She charges $3.50 for each one. Write a function

to model Marie's profit?
Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Given is the Overhead charges = 25 dollars.

Making charge of each barrette = 1.25 dollars.

Let's assume the number of barrette that she makes = x

So the Cost function would be, C(x) = 1.25x + 25.

She sell each piece for 3.50 dollars.

So the Revenue function would be, R(x) = 3.50x


We know the Profit function is given by the difference of Revenue function and Cost function.

Profit function = Revenue function - Cost function

P(x) = R(x) - C(x)

P(x) = 3.50x - (1.25x + 25)

P(x) = 3.50x - 1.25x - 25

P(x) = 2.25x - 25

Hence, Marie's Profit would be P(x) = 2.25x - 25.

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Total angle for the pie chart = 360°

13 out of 60 =    13 / 60

Angle for it =    13 / 60 * 360 = 13 * 6 = 78°

Angle used = 78°
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2. Hasil dari<br>+<br>9,1-2<br>5<br>=<br>A. 6,5<br>B. 7,5<br>7<br>C. 6<br>30<br>D. 7<br>7<br>30​
sasho [114]

Answer:

Itu mudah 2.18

A.11

B.19

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D.44

6 0
3 years ago
B-30.45=95.28 what is the answer
mixer [17]

Answer:

B = 125.73

Step-by-step explanation:

<u>Step 1:  Add 30.45 to both sides</u>

<u />B - 30.45=95.28

B +(- 30.45 + 30.45)=(95.28 + 30.45)

B = 125.73

Answer:  B = 125.73

6 0
3 years ago
A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters
natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that p = 0.7

20 eligible voters were randomly selected from the population of all eligible voters.

This means that n = 20

What is the probability that fewer than 11 of them will vote?

This is:

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308

P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120

P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039

P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010

P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002

P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0
3 years ago
What are the zeros of the function f(x) = 10x2 + 9x + 2?
Gnom [1K]

Answer:

x = -4/5  and -1/2

Step-by-step explanation:

"Finding zeroes" means find the x-values that make f(x) = 0, so we have...

0 = 10x² + 9x + 2

Use quadratic equation to solve...

x = [-9 ± √(9² - 4(10)(2))]/[2(10)]

x = [-9 ± √(81 - 80)]/20

x = [-9 ± √1]/20

x = [-9 ± 1]/20

x = (-9 + 1)/20    and (-9 - 1)/20

x = -8/20      and -10/20

x = -4/5  and -1/2

8 0
3 years ago
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