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likoan [24]
3 years ago
9

An electron in a cathode-ray beam passes between 2.5-cm-long parallel-plate electrodes that are 5.6 mm apart. A 2.5 mT , 2.5-cm-

wide magnetic field is perpendicular to the electric field between the plates. The electron passes through the electrodes without being deflected if the potential difference between the plates is 600 V . Part A What is the electron's speed? Express your answer to two significant figures and include the appropriate units. v v = nothingnothing SubmitRequest Answer Part B If the potential difference between the plates is set to zero, what is the electron's radius of curvature in the magnetic field? Express your answer to two significant figures and include the appropriate units. r r = nothingnothing
Physics
1 answer:
ziro4ka [17]3 years ago
7 0

A) 4.3\cdot 10^7 m/s

For an electron moving in a region with both electric and magnetic field, the electron will move undeflected if the electric force on the electron is equal to the magnetic force:

qE= qvB

which means that the speed of the electron will be

v=\frac{E}{B}

where

E is the magnitude of the electric field

B is the magnitude of the magnetic field

In this problem,

B=2.5 mT=0.0025 T is the intensity of the magnetic field

The electric field can be found as

E=\frac{V}{d}

where

V = 600 V is the potential difference between the electrodes

d=5.6 mm=0.0056 m is the distance between the electrodes

Substituting,

E=\frac{600 V}{0.0056 m}=1.07\cdot 10^5 V/m

So the electron's speed is

v=\frac{1.07\cdot 10^5 V/m}{0.0025 T}=4.3\cdot 10^7 m/s

B) 9.8\cdot 10^{-2} m

The radius of curvature of an electron in a magnetic field can be found by equalizing the centripetal force to the magnetic force:

m\frac{v^2}{r}=qvB

where

m is the electron mass

v is the speed

r is the radius of curvature

q is the charge of the electron

Solving for r, we find

r=\frac{mv}{qB}=\frac{(9.11\cdot 10^{-31} kg)(4.3\cdot 10^7 m/s)}{(1.6\cdot 10^{-19} C)(0.0025 T)}=9.8\cdot 10^{-2} m

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inna [77]

Answer: 10 s, 30 m/s , 150 m

Explanation:

Given

The speed of motorcyclist is  u_1=15\ m/s

The initial speed of a police motorcycle is u_2=0\ m/s

acceleration of police motorcycle is a=3\ m/s^2

Police will catch the motorcyclist when they traveled equal distances

distance traveled by motorcyclist in time t is

\Rightarrow s_1=15\times t

Distance traveled by Police in time t is

\Rightarrow s_2=u_2t+\frac{1}{2}at^2\\\Rightarrow s_2=0+0.5\times 3\times t^2

put s_1=s_2

\Rightarrow 15t=0.5\times 3\times t^2\\\\\Rightarrow t(1.5t-15)=0\\\\\Rightarrow t=\dfrac{15}{1.5}=10\ s

Police officer's speed at that time is

\Rightarrow v_2=u_2+at\\\Rightarrow v_2=0+3\times 10=30\ m/s

Distance traveled by each vehicle is

\Rightarrow s_1=s_2=15\times t=15\times 10=150\ m

8 0
3 years ago
Big Al stands on a skateboard at a rest and throws a 0.5-kilogram rock at a velocity of 10.0 m /sec. Big Al moves back at 0.05 m
Vlada [557]
Let
his and skateboard's combined mass is x
we know
F1=-F2
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4 0
3 years ago
. A chemistry student’s height is measured at 68.5 inches. How tall is the student in cm?
tatiyna

1 inch = 2.54 centimeters

All we need to do is multiply.

68.5 * 2.54 = 173.99cm

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3 0
4 years ago
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Imagine you’re an engineer making a string of battery powered holiday lights. If a bulb burns out current cannot flow through th
Anit [1.1K]

Answer:

The 2 light bulbs can be connected in parallel to each other to avoid disconnection when one bulb burns out.

Explanation:

The parallel connection is required not series. A parallel connection is the connection of electronic components (e.g bulbs, LED, resistors, capacitors etc) in such a way that the same voltage is supplied across the ends of the components.  While in a series connection, the components are connected to each other end-to-end.

As regard the question, parallel connection ensures that the brightness any of the bulbs is not affected with respect to the other bulbs. And other bulbs continue to function when any burns out. The 2 light bulbs should be connected in parallel to the baterry to avoid disconnection of all the bulbs.

4 0
4 years ago
A mover loads a 100 kg box into the back of a moving truck by
NeX [460]

Answer:

2.7

Explanation:

The following data were obtained from the question:

Mass (m) of box = 100 Kg

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

Mechanical advantage of a ramp is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is given by:

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MA= L/H

With the above formula, we can obtain the mechanical advantage of the ramp as follow:

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

MA = 4/1.5

MA = 2.7

Therefore, the mechanical advantage of the ramp is 2.7

3 0
3 years ago
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