Answer: 4.4 cm.
Explanation:
Rise of water in the smaller tube= h1=8.8 centimeter(cm)
Radius of the smaller tube= r
Rise of water in the larger tube= h2 (in centimeter).
The radius of the larger tube is twice that of the smaller tube means that;
The radius in the larger tube is 2r ( 2 multiply by the radius r, of the smaller tube)
Using Jurin's law;
height or rise of liquid is inversely proportional to its radius, r.
That is; hr= constant.
Therefore, we have;
h1 × r1 = h2 × r2.
Rise in smaller tube × radius of the smaller tube = height of the larger tube × radius of the larger tube.
8.8 cm × r = h2 × 2r
= (8.8cm)r = (h2) 2r
Divide both sides by 2r, we then have;
8.8cm r/ 2r = h2
h2= 4.4cm
Therefore, the height or rise in large tube is half of that of the smaller tube.
Refraction is caused by any wave crossing the boundary out of one substance and into another one. The two different substances may be no more than two parcels of air at different temperatures.
Answer and Explanation:
In optics, a CoC(Circle of Confusion) is defined the minimum cross section of a paraxial bundle of rays made by a lens which is sphero-cylindrical type and can be viewed as an optical spot, which do not converge perfectly at the focus while a point source is being imaged due to spherical aberration.
The Circle of Confusion is also referred to as circle of indistinctness or a blur spot
Answer:
F'= 4F/9
Explanation:
Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :
...(1)
Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :
.....(2)
Dividing equation (1) and (2), we get :
Hence, the correct option is (d) i.e. " 4F/9"
Answer:
3600 kg
Explanation:
From the question,
Density = Mass/Volume
D = M/V.............................. Equation 1
Where D = Density of the substance, M = mass of the substance, V = Volume of the subtance.
Make M the subject of the equation
M = D×V ............................ Equation 2
Given: D = 1200 kg/m³, V = 3 m³.
Substitute these values into equation 2
M = 1200×3
M = 3600 kg.
Hence the mass of the substance is 3600 kg
